@mfalkvidd said:
I am using them at 12V so the power would be ~4W. Not too much but still enough to get the sink hot!
The voltage makes no difference. 5A is still 5A.
you are right brain fart
this kind of optic fiber is probably only plastic so for a full DIY , you can use also fishing wire with a big power led or an old chistmass tree optic fiber lighted.....
@tbowmo more out of curiosity, and from someone that just got started on electronics, so please sorry if this sounds like very noob, but, would it not be safer to plug the V_TARGET LED to the +3.3v pin? How do you ensure that the resistor on the V_TARGET will have constant voltage and that will not blow from over voltage if the VCCio pin is depended on the the Motherboard power?
Thank You and nice work
I've been using processing.org to capture data from Arduinos. I haven't tried with an RPi yet, but the link here is dedicated to just that.
Processing is more geared for doing really fancy graphics, but its ability to capture data and put it to a file is great, and, of course, send data to the Arduino.
I am inexperienced in interprocess communication, but, apparently processing can put the data out to MQTT check this link
Let me know how that works out for you!
@NeverDie said in The Harvester: ultimate power supply for the Raybeacon DK:
Edit: This guy found another couple of possibilities as to what the E50D chip might be: https://www.electroschematics.com/pfm-module-circuit-surgery/
I have the same board as this guy. I removed the LED and resistor because they are on the input side, so they are almost useless anyway. For a board such as this, with a promised 0.9v startup voltage on the input side and a promised 5v on the output side, they really should have been attached to the output, not the input, to show roughly when it is that the board is producing useable output.
At a 20mv "keep alive" input voltage, the input measures 0.5ma using a uCurrent Gold. That means the keep alive energy is 10 microWatts. Offhand, for the application we've been discussing on this thread, I suspect that number is too high to be practically useful, because at only 20mv input we'd be collecting far less than 0.5ma current from a tiny panel. At least now we know.