How to get longest battery life
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@Nca78 said:
I will give it a try "the cheap way" :)
5.5V solar panel, small lipo taken from a 2$ mp3 player and CN3063 to manage the charge.just make sure you share your results ;)
@korttoma said:
just make sure you share your results ;)
I will of course, but at the moment it's a bit early I just prepared 2 PIRs, 2 panels and soldered CN3063 and MCP73831 on adapter boards. I will compare the two, CN3063 is supposed to be better at this task but you never know...
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What about using 2 of these in parallel? That would give 5200 mAh at 3.7v
Lithium ion rechargeableVera Plus running UI7 with MySensors, Sonoffs and 1-Wire devices
Visit my website for more Bits, Bytes and Ramblings from me: http://dan.bemowski.info/ -
What about using 2 of these in parallel? That would give 5200 mAh at 3.7v
Lithium ion rechargeable@dbemowsk I would put only one. Capacity is already very good and you won't gain battery life by using 2 cells as they self-discharge in around one year...
And if you buy those, just throw away the charger. It's made with very low quality charging ICs that might destroy the batteries... -
What about using 2 of these in parallel? That would give 5200 mAh at 3.7v
Lithium ion rechargeable@dbemowsk said:
What about using 2 of these in parallel? That would give 5200 mAh at 3.7v
Lithium ion rechargeableIt seems to defeat the purpose of buying a $1 PIR if it takes $16 to make it work in your use case. For instance, the last time I checked, you could buy a really nice, small, highly integrated Panasonic PIR with about 1ua standby current for around $19.
Of course, it hardly matters either way if you're making just one. But if you want to make a lot of them (and I don't know that you do), maybe it becomes a consideration.
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So I thought since the PIRs that I have say for the chip that the voltage minimum is 3 volts. If I am going to make sensors that run on 2 AA batteries, once the voltage drops a bit the PIR will be useless, thus decreasing the usable battery life for that sensor even though the pro mini and the radio will run at a significantly lower voltage. What about using something like this to step up the voltage just for the PIR, but leaving the radio and arduino directly connected to the battery? This one will work down to 0.8 volts.
Step up booster 1
Or this one which works down to 1.8 volts which is about what the drop off point of the radio and pro mini is. Step up booster 2
I figure the current draw from the PIR would be low enough at 65ma tripped, and a quiscent current of 50ua for the second step up module (can't find quiscent current for the first one) that it shouldn't be too much of a drain on the battery, correct?@dbemowsk said:
So I thought since the PIRs that I have say for the chip that the voltage minimum is 3 volts. If I am going to make sensors that run on 2 AA batteries, once the voltage drops a bit the PIR will be useless, thus decreasing the usable battery life for that sensor even though the pro mini and the radio will run at a significantly lower voltage. What about using something like this to step up the voltage just for the PIR, but leaving the radio and arduino directly connected to the battery? This one will work down to 0.8 volts.
Step up booster 1
Or this one which works down to 1.8 volts which is about what the drop off point of the radio and pro mini is. Step up booster 2
I figure the current draw from the PIR would be low enough at 65ma tripped, and a quiscent current of 50ua for the second step up module (can't find quiscent current for the first one) that it shouldn't be too much of a drain on the battery, correct?Anyhow, to answer your question, I have a hunch those voltage converters would drain your battery even faster for a number of reasons:
- Inefficiency introduced by the up-converter itself. Purely guessing, but it might be only 30-60% efficient at converting lower voltages and currents.
- It takes a lot more low voltage current to produce a higher voltage current. Ultimately, your battery is limited by the amount of mah in it, and so those higher currents will drain it faster.
- The quiescent current you already mentioned.
#3 could be managed by using a storage capacitor and running the up-converter only intermittently, as needed, to recharge the capacitor. For instance, you could use a voltage detector to decide when to turn it on (for instance, maybe http://www.digikey.com/product-detail/en/rohm-semiconductor/BD49K25G-TL/BD49K25G-TLCT-ND/3693402 , which itself draws less than 1ua of current while monitoring the voltage). However, I don't see an easy way around #1 and #2, except maybe this: run on battery power only (i.e. no boosting) until your batteries are down to around 2.4-2.5v, and only then turn on your booster circuit. That would, in fact, give you at least some extra run-time versus just giving up and replacing the batteries after they became drained down to 2.4-2-5v. You might also want to boost to a lower voltage than 3.3v, as that would mitigate #2.
Maybe others here also have suggestions on how you might approach it.
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@dbemowsk said:
What about using 2 of these in parallel? That would give 5200 mAh at 3.7v
Lithium ion rechargeableIt seems to defeat the purpose of buying a $1 PIR if it takes $16 to make it work in your use case. For instance, the last time I checked, you could buy a really nice, small, highly integrated Panasonic PIR with about 1ua standby current for around $19.
Of course, it hardly matters either way if you're making just one. But if you want to make a lot of them (and I don't know that you do), maybe it becomes a consideration.
@NeverDie I was just using that link as an example. Here is a 10 pack for $9.99 US. That's $1 per battery. And, these boast that they can supply 5800 mAh. Not sure if I believe that, but even if it could source half of that, it should last a while. Also, being rechargeable I wouldn't have to keep buying batteries.
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I'd wadger there's 0.0000% chance of them being 5400mah. The best that I'm aware of are the one's made by panasonic, and those are reputedly 3400mah.
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@dbemowsk you won't get nearly as the half of that with those cheap cells. I've seen some on Aliexpress boasting 9600mAh and in the end user comments pointed to capacity around 1000mAh...
I can buy some cheap ones in local electronic market here in Vietnam, the cheapest are 1.5$ and only 1200mAh. If you want genuine 3400mAh it's around 8$...
I would buy from Aliexpress with good seller and lot of comments so you can have some feedback on the real capacity of the batteries. -
Let's put this in perspective: according to Wikipedia ( https://en.wikipedia.org/wiki/D_battery), an Energizer Alkaline D-cell battery has 20,000mah at a 25ma draw, which is obviously far higher than the average current draw of the modified PIR. Also in the D-cell's favor is that it has comparatively low self discharge as well as little risk of spontaneously bursting into flames....
So, you'd definitely get at least 2 years, and probably 3+ years from a pair of D-cells. Maybe a lot more years than that even. Good enough? Those are just some lower bound numbers, but even so, that sounds like a winner to me. :smile: By all means, though, use a sharper pencil and see what you figure it at. Of course, it will be a larger physical package than if you were running from a coin cell, but for the low cost, simplicity of construction, and long battery life, it seems like a worthwhile trade-off to me. :grinning:
Wow. I really didn't expect anything worthwhile to come from this thread, but now I'm glad I stuck with it. :smiley:
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Let's put this in perspective: according to Wikipedia ( https://en.wikipedia.org/wiki/D_battery), an Energizer Alkaline D-cell battery has 20,000mah at a 25ma draw, which is obviously far higher than the average current draw of the modified PIR. Also in the D-cell's favor is that it has comparatively low self discharge as well as little risk of spontaneously bursting into flames....
So, you'd definitely get at least 2 years, and probably 3+ years from a pair of D-cells. Maybe a lot more years than that even. Good enough? Those are just some lower bound numbers, but even so, that sounds like a winner to me. :smile: By all means, though, use a sharper pencil and see what you figure it at. Of course, it will be a larger physical package than if you were running from a coin cell, but for the low cost, simplicity of construction, and long battery life, it seems like a worthwhile trade-off to me. :grinning:
Wow. I really didn't expect anything worthwhile to come from this thread, but now I'm glad I stuck with it. :smiley:
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Looking at the costco price for D-cell batteries (http://www.costco.com/Duracell-D-Alkaline-Batteries-14-Unit%2C-2%2B-Pack-Pricing.product.100322549.html), two D-cells would cost just over $1 plus tax.
So, rough BOM:
$1 for batteries
$1 for PIR
$1(?) for battery holder
$4 for atmega328p+RFM69HW mote (maybe $2 for an nrf24L01 mote)Total: around $6 to $8
At that price you could afford lots of them, which would also offer a way to correct for possible false positives.
