@mfalkvidd Thank you for the quick and informative response. I'm new to Arduino and didn't know how to look for this type of information. I think i will try activating the internal pullup resistor as I have already done for my door switches. If this does not work then I will attempt to build my own voltage divider circuit. I will post my findings in the coming week.

It worked perfectly. I found a sketch in the forums for two switches with interrupts and wired up two glass break sensors. The sensors can be found on amazon for 12 bucks "Interlogix Glassbreak Shock Detector, White (5150W)". Thanks for the help!

It worked perfectly. I found a sketch in the forums for two switches with interrupts and wired up two glass break sensors. The sensors can be found on amazon for 12 bucks "Interlogix Glassbreak Shock Detector, White (5150W)". Thanks for the help!

@mortommy Thanks for the schematic. This seems a more complicated than I was hoping. Do you think activating the internal pullup resistor would be a more appropriate first step? Are there any disadvantages to this approach?

@mfalkvidd Thank you for the quick and informative response. I'm new to Arduino and didn't know how to look for this type of information. I think i will try activating the internal pullup resistor as I have already done for my door switches. If this does not work then I will attempt to build my own voltage divider circuit. I will post my findings in the coming week.

I have found some nice glass break sensors that don't require power. I looked up the data sheet (http://static.interlogix.com/library/75803_shock_sensor_ds.pdf) and it has a certain resistance when idle 14-24Ω. And when the sensor is tripped it has a resistance > 1MΩ. My question is this: will the arduino register 1 MΩ as open? I have the switch sketch working for door sensors and was really hoping to expand to glass break. Any help is appreciated.