measuring VCC (internal) to percentage



  • I managed to measure the Vcc with the atmega with this script:

    long readVcc() {
      // Read 1.1V reference against AVcc
      // set the reference to Vcc and the measurement to the internal 1.1V reference
      #if defined(__AVR_ATmega32U4__) || defined(__AVR_ATmega1280__) || defined(__AVR_ATmega2560__)
        ADMUX = _BV(REFS0) | _BV(MUX4) | _BV(MUX3) | _BV(MUX2) | _BV(MUX1);
      #elif defined (__AVR_ATtiny24__) || defined(__AVR_ATtiny44__) || defined(__AVR_ATtiny84__)
        ADMUX = _BV(MUX5) | _BV(MUX0);
      #elif defined (__AVR_ATtiny25__) || defined(__AVR_ATtiny45__) || defined(__AVR_ATtiny85__)
        ADMUX = _BV(MUX3) | _BV(MUX2);
      #else
        ADMUX = _BV(REFS0) | _BV(MUX3) | _BV(MUX2) | _BV(MUX1);
      #endif  
     
      delay(2); // Wait for Vref to settle
      ADCSRA |= _BV(ADSC); // Start conversion
      while (bit_is_set(ADCSRA,ADSC)); // measuring
     
      uint8_t low  = ADCL; // must read ADCL first - it then locks ADCH  
      uint8_t high = ADCH; // unlocks both
     
      long result = (high<<8) | low;
     
      result = 1125300L / result; // Calculate Vcc (in mV); 1125300 = 1.1*1023*1000
      return result; // Vcc in millivolts
    }
    

    I have currently this formula to set it to percentage:

      float batteryV  = readVcc();
      int batteryPcnt = (((batteryV - 2000) / 1200) * 100 );
    

    readVcc outputs the vcc voltage. I want to set it to percentage. @ what voltage should I cut it off to 0%? What is the best formula?

    Full AA alkalines are around 1.6V?


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