Using Sleep RISING mode with momentary switch?

[Sergio Rius]

I'm trying to make a sensor for garden doorbell duties. So I built a battery powered sensor with a momentary switch wired to pin 3 using a pull down resistor.
My intention is to make it detect when someone pushes the button (obviously) but not changing the state to off as the button is released, but using a timer.
With that maneuver I want to be able to make a camera send me the video while that timer is active.
Also, as the sensor is battery powered, It will also sleep for a longer time and wake on the pin interrupt.

So I thought that it could be clean and nice only waking the sensor on the button pushed and only changing the amount of sleep.
In my code I used the sleep function with the RISING mode, but I found that it triggers with the on, but also the off state of the switch.

I made a nasty hack and put a delay to neglect the pulling up of the button, but is there any solution?

There's my code:

// Loop will iterate on changes on the BUTTON_PINs
void loop() 
{
  uint8_t value = digitalRead(PRIMARY_BUTTON_PIN);
  unsigned long sleepTime = value==HIGH ? SHORT_PAUSE : SLEEP_TIME;
  send(msg.set(value==HIGH ? 1 : 0));
  digitalWrite(FEEDBACK_LED_PIN, value);

#ifdef MY_DEBUG
   Serial.println(value==HIGH ? "Button press detected!" : "Reset!");
   Serial.print("New values: "); Serial.print(value); Serial.print(" / "); Serial.println(sleepTime);
#endif

  SendBatteryLevel();

  delay(5000);
  
  // Sleep until something happens with the sensor
  sleep(PRIMARY_BUTTON_PIN-2, RISING, sleepTime);
}```

[mfalkvidd]

@Sergio-Rius delay is actually the easiest way to do it :) Either that, or build a hardware debouncer.

See also https://www.mysensors.org/build/binary for how to use the bounce2 library to handle debouncing. That solution doesn't support interrupts though, so delay is probably a better solution for your node.