Battery sensor measure for li-ion cells?



  • Hello. like i told on other topics , i'm finishing my first "mysensor" conected to vera lite ,battery powered (2xtermistor+light sensor) that i will present later on forum soon as its working. its all working except battery percentage.
    Second the example i follow,it says:

     // 1M, 470K divider across battery and using internal ADC ref of 1.1V
       // Sense point is bypassed with 0.1 uF cap to reduce noise at that point
       // ((1e6+470e3)/470e3)*1.1 = Vmax = 3.44 Volts
       // 3.44/1023 = Volts per bit = 0.003363075
       float batteryV  = sensorValue * 0.003363075;
       int batteryPcnt = sensorValue / 10;
    

    this is part of "mysensor battery sensor example"

    Its a simple voltage divider and calculation of volt per bit and after that send percentage to my vera.
    BUT i'm using li-ion batteries , 3.6v cell, 2 cell=7.2v or +-8.2v on full charge.
    AND there comes my problem.
    Where this calculation make reference to what is 100%(8.2v) and what is 0%(6.4v)?
    it only will say 0% its a flat ...Dead...li-ion cell:/

    Thank you


  • Mod

    The reference tells the chip what should be regarded as maximum. So if you set 1.1V as reference, any voltage above 1.1V will result in a reading of 1023.

    You either need to adjust your voltage divider so the "middle" point is at 1.1V or below (with 8.2V you could use something like 1Mohm + 120kohm), or use a different method (like the "secret" method). You could also switch to using the "standard" reference (of 5V) and your 1M+470k voltage divider.

    Edit: The "secret" (stupid name!) method required that you don't use a voltage regulator, so it is not applicable in your case. Go for 1M+120k voltage divider or use the standard reference.



  • Ok. I use vreg. Its waste less battery than stepup modules(second i read) .
    But what about Set the 0% .0 will be aa flat cell,right?

    I already use reference as default(3.3v on my promini)


  • Hardware Contributor

    I've successfully used these calculations, resistors and voltage levels for different number of AAs in series with the 1.1V ref.

    Internal_ref=1.1V, res=10bit=2^10-1=1023, 2AA: Vin/Vbat=470e3/(1e6+470e3), 4AA: Vin/Vbat=1e6/(1e6+5e6), 3AA: Vin/Vbat=680e3/(2.5e6+680e3)
    
    Vlim = 1.1*Vbat/Vin = 6.6 V (Set to Vmax ?)
    Volts per bit = Vlim/1023 = 0.006452
    Vmin = 4.3V (Min input voltage to regulator according to datasheet. (?) )
    Vmax = 6.6V (Known or desired voltage of full batteries. If not, set to Vlim.)
    Vpercent = 100*(Vbat-Vmin)/(Vmax-Vmin)
    

    So if you use the 3.3V Arduino Pro Mini through its internal vreg, I'd set the Vmin (0%) ~1V above 3.3V i.e. 4.3V, by default. If your stuff supplied by this vreg-out is capable of going below 3.3V you could lower your Vmin, but then you have to use the 1.1V ref.
    Else, when using "high" voltages like in your case it's hard to optimize the resistors and then better to also use a higher reference, like 3.3 och 5V Vcc.

    I'd suggest you to use the 3.3V (default) reference and standard voltage divider (1M+470k). The calculation are then

    Vlim = 3.3*(1e6+470e3)/470e3 = 10.32 V
    Volts per bit = Vlim/1023 = 0.010089224434
    Vmin = 4.3V (Min input voltage to regulator)
    Vmax = 8.2V (+ some margin)
    Vpercent = 100*(Vbat-Vmin)/(Vmax-Vmin)
    

    And of course in your code, there will be something like...

    float batteryV  = sensorValue * 0.010089224434;
    int batteryPcnt = static_cast<int>(((batteryV-VMIN)/(VMAX-VMIN))*100);


  •  Vpercent = 100 x (Vbat-Vmin) / (Vmax-Vmin)    ! ! ! ! ! ! ! ! ! 
    

    THAT IS THE WINNER CALCULATION!! is just that what i'm locking for 🙂 but i coldn't reach by my self

    Thank you very much.


  • Hardware Contributor

    👍

    Some people prefer to use the 'map()' function instead. It does the same job.



  • one more function that i din't know:P

    long map(long x, long in_min, long in_max, long out_min, long out_max)
    {
      return (x - in_min) * (out_max - out_min) / (in_max - in_min) + out_min;
    }
    

    For now it will stay with voltage regulator and 7,2v (2 cells battery), but in case I want save even more battery I can use only 1 cell (3.7v) and connect it directly to vcc on my 8mhz pro mini and remove led and 3.3v regulator.

    My question is , atmel326p handle up to 5v directly on Vcc,even my 8mhz one, but what happens to my analog reference ,if i set analog reference( default ), as it is right now, and my battery fluctuate between 4.2V and 3.2V when start discharge? Reference will fluctuate as well and affect my battery measure ,right? how they handle that problem?


  • Hardware Contributor

    @Tmaster
    Whenever you connect your battery straight to Vcc, I can't see any reason not use the internal voltage monitoring method (as @mfalkvidd linked to above).

    Last I heard was that 3.7V ment a high risk to kill the nRF radio module. You might want to look up how people have handled that before you proceed.



  • ah! i was so focus on arduino that i forgot the radio. but i know about 3.3 v from nrf24.
    When its powered by transformer ,i use 5v arduinos and this module for the nrf24. is v reg :
    http://www.ebay.com/itm/New-Sale-Socket-Adapter-Module-Board-for-8PIN-NRF24L01-Wireless-Module-/191353332066?hash=item2c8d8c2162:g:QnUAAOxyBotTX0mW


  • Hardware Contributor

    Great information here! I was building my own method for getting battery percentage for my 2AA battery powered node and tried to understand the calculations. Here is my piece of code. What do you guys think? Everything's right?

    // define values for the battery measurement
    #define R1 = 1e6;
    #define R2 = 470e3;
    #define VMIN = 1.8;
    #define VMAX = 3;
    #define ADC_PRECISION = 1023;
    
    int getBatteryPercentage() {
    
      // read analog pin value
      int inputValue = analogRead(BATTERY_SENSE_PIN);
      
      // calculate the max possible value and therefore the range and steps
      float voltageDividerFactor = (R1 + R2) / R2;
      float maxValue = voltageDividerFactor * VMAX;
      float voltsPerBit = maxValue / ADC_PRECISION;
    
      float batteryVoltage = voltsPerBit * inputValue;
      //int batteryPercentage = ((batteryVoltage-VMIN)/(VMAX-VMIN))*100;
      int batteryPercentage = map(batteryVoltage, 0, maxValue, 0, 100);
    
      return batteryPercentage;
    }
    

    The 2 lines for the batteryPercentage should do exactly the same. Prefer the 2nd one though, it's more readable for me.


  • Hardware Contributor

    @LastSamurai
    About this line:

    float maxValue = voltageDividerFactor * VMAX;
    

    You should use your Adc reference voltage here, not VMAX. If it's a 2AA node you probably use 1.1V internal ref.


  • Hardware Contributor

    Thanks! I updated the code (had some errors in the define statements and now got this:

    #include <SPI.h>
    #include <MySensor.h>  
    #include <DHT.h>  
    
    #define CHILD_ID_HUM 0
    #define CHILD_ID_TEMP 1
    #define HUMIDITY_SENSOR_DIGITAL_PIN 3
    
    // define values for the battery measurement
    #define R1 1e6
    #define R2 470e3
    #define VMIN 1.8
    #define VMAX 3
    #define ADC_PRECISION 1023
    #define VREF 1.1
    
    MySensor gw;
    DHT dht;
    unsigned long SLEEP_TIME = 300000; // Sleep time between reads (in milliseconds)
    float lastTemp;
    float lastHum;
    boolean metric = true; 
    MyMessage msgHum(CHILD_ID_HUM, V_HUM);
    MyMessage msgTemp(CHILD_ID_TEMP, V_TEMP);
    int oldBatteryPcnt = 0;
    int BATTERY_SENSE_PIN = A0;
    
    
    void setup()  
    { 
         // use the 1.1 V internal reference
      #if defined(__AVR_ATmega2560__)
         analogReference(INTERNAL1V1);
      #else
         analogReference(INTERNAL);
      #endif
    
      gw.begin();
      dht.setup(HUMIDITY_SENSOR_DIGITAL_PIN); 
    
      // Send the Sketch Version Information to the Gateway
      gw.sendSketchInfo("Humidity", "1.0");
    
      // Register all sensors to gw (they will be created as child devices)
      gw.present(CHILD_ID_HUM, S_HUM);
      gw.present(CHILD_ID_TEMP, S_TEMP);
      
      metric = gw.getConfig().isMetric;
    }
    
    void loop()      
    {  
       int batteryPcnt = getBatteryPercentage();
    
       Serial.print("Battery percent: ");
       Serial.print(batteryPcnt);
       Serial.println(" %");
    
       if (oldBatteryPcnt != batteryPcnt) {
         // Power up radio after sleep
         gw.sendBatteryLevel(batteryPcnt);
         oldBatteryPcnt = batteryPcnt;
       }
      
      // totally random test values
      gw.send(msgTemp.set(42, 1));
      gw.send(msgHum.set(42, 1));
    
      gw.sleep(SLEEP_TIME); //sleep a bit
    }
    
    int getBatteryPercentage() {
    
      // read analog pin value
      int inputValue = analogRead(BATTERY_SENSE_PIN);
      
      // calculate the max possible value and therefore the range and steps
      float voltageDividerFactor = (R1 + R2) / R2;
      float maxValue = voltageDividerFactor * VREF;
      float voltsPerBit = maxValue / ADC_PRECISION;
    
      float batteryVoltage = voltsPerBit * inputValue;
      float batteryPercentage = ((batteryVoltage-VMIN)/(VMAX-VMIN))*100;
      //int batteryPercentage = map(batteryVoltage, 0, maxValue, 0, 100);
    
      return batteryPercentage;
    }
    

    I am using 2 1.5V aa batteries, but somehow I get a percentage of 136%. Whats wrong there?
    Using the map part instead I get 100%, so some values is way to big somehow.


  • Hardware Contributor

    @LastSamurai
    If I were you I would:
    a. Measure battery voltage to know what to expect.
    b. Debug by printing out the raw sensor value 'inputValue'. (0 or 1023 likely means a hw issue).
    c. Change VMAX to 3.2, 3.3 or maxValue.
    d. Change the line

      float batteryPercentage = ((batteryVoltage-VMIN)/(VMAX-VMIN))*100;
    

    to

      int batteryPercentage = static_cast<int>(((batteryVoltage-VMIN)/(VMAX-VMIN))*100);

  • Hardware Contributor

    Ok I added the change, removed everything but the battery/voltage code and tried it out. Using a serial to usb adapter I got the right values.
    Then I readded the network and sleep stuff and suddenly I am getting these 136% percent again. Any idea why? Could sleeping or the network somehow interfere with the measurements?


  • Hero Member

    @LastSamurai Everything is related to VMAX in your case. Have you measured the actual voltage of the batteries..? The type of battery used can explain the 136% upload-24c946fc-3ac4-4897-9bc2-b8203650a0ac

    Using the calculation below you will never get an above 100% reading 😉

    int batteryPcnt = constrain(map(batteryVoltage, VccMin, VccMax, 0, 100),0,100); // and map to the 0-100% range
    

  • Hardware Contributor

    The actual voltage was about 2.7-2.8V. So my values should be right?! I will do some more testing soon.

    Are you sure about constrain and map? I am pretty sure the map call already maps the values to 0..100. So no constrain needed.

    Is it possible that

    #define VMAX 3
    // has to be
    #define VMAX 3.0
    

  • Hardware Contributor

    @LastSamurai
    I think you should note what the map() reference says about constrain and integer math. Try to use mV instead.


  • Hardware Contributor

    @m26872 Thanks! For me thats strange behaviour but it seems you guys are absolutely right!
    What do you mean mV? Using VMAX 3000 instead of 3?


  • Hardware Contributor

    @LastSamurai
    As input to map(), yes. And that goes for Vbat and Vmin as well of course.


  • Hardware Contributor

    @Tmaster
    I'd like to add a few things about the settings a Vmin and Vmax.

    If you get a Vbat value outside of [Vmin Vmax] the calculation would give a negative result. Since it's then sent as an uint8_t, it'll not be easy read or meaningful. Due to this it's sometimes a good advice to make the interval wider, use a constraint or handle the exceptions.

    Vmin 4.3V is a conservative limit. The APM internal vreg (ldo?) is probably working a lot lower depending on the load. You have to find out yourself.


Log in to reply
 

Suggested Topics

8
Online

11.4k
Users

11.1k
Topics

112.7k
Posts