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  3. Arduino freezes when I'm writing EEPROM

Arduino freezes when I'm writing EEPROM

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  • J jhonnygolpe

    Hi again. I've just tried your advises and, of course, I've solve my compilation errors. Thanks for your help !!
    But I can't write and rewrite the EEPROM correctly yet. It seems like I'm writing on a new address an y time, so in 2 or 3 times of savind data, arduino freezes.
    Now I've defined

    #define EEPROM_LOCAL_ADDRESS 2
    

    and after just 2 or 3 times of using

    saveState(EEPROM_LOCAL_ADDRESS,  (uint8_t)newPosition);
    

    arduino freezes.
    I've a test code, very similar, but without saving or reading from the EEPROM and works fine, so I suppose it's my fault using correctly those functions.
    Thanks again

    YveauxY Offline
    YveauxY Offline
    Yveaux
    Mod
    wrote on last edited by
    #8

    @jhonnygolpe What Arduino hardware are you using?
    Did you try writing to another address?

    http://yveaux.blogspot.nl

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    • J Offline
      J Offline
      jhonnygolpe
      wrote on last edited by
      #9

      Well, i'm working with Arduino Uno, directly connected to the 220V/5v converter, so the power can't be the problem. I will enclose the code, and to help the reading of it, i'll try to explain it. On the Arduino there are connected a DHT22 sensor, and 2 relays and 2 buttons to control the blinds. I'm using my former motorized blinds, with its wall-mounted controllers (now one button to UP, another to DOWN). I want to use the previous controllers, and add remote control to move the blinds. So in the loop() function, I check if any of the buttons has been pressed, or if it's the time to send some info to the gateway. I use to have problems when I move down the blind remotely, with the receive function. With the debug activated, it seems to freeze after finishing the downAction() function...
      By the time, I'm gonna try the code with another arduino and another EEPROM address.
      As you will see I'm using another DEBUG class, very similar to the mysensors'oneSerialDebug.h blindsControlEL.ino

      mfalkviddM 1 Reply Last reply
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      • J jhonnygolpe

        Well, i'm working with Arduino Uno, directly connected to the 220V/5v converter, so the power can't be the problem. I will enclose the code, and to help the reading of it, i'll try to explain it. On the Arduino there are connected a DHT22 sensor, and 2 relays and 2 buttons to control the blinds. I'm using my former motorized blinds, with its wall-mounted controllers (now one button to UP, another to DOWN). I want to use the previous controllers, and add remote control to move the blinds. So in the loop() function, I check if any of the buttons has been pressed, or if it's the time to send some info to the gateway. I use to have problems when I move down the blind remotely, with the receive function. With the debug activated, it seems to freeze after finishing the downAction() function...
        By the time, I'm gonna try the code with another arduino and another EEPROM address.
        As you will see I'm using another DEBUG class, very similar to the mysensors'oneSerialDebug.h blindsControlEL.ino

        mfalkviddM Offline
        mfalkviddM Offline
        mfalkvidd
        Mod
        wrote on last edited by
        #10

        @jhonnygolpe said:

        With the debug activated, it seems to freeze after finishing the downAction() function...

        Are you sure it exits the downAction? How about adding debug statements before and after each funtion call in loop()? That would help determine which fuction freezes.

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        • J Offline
          J Offline
          jhonnygolpe
          wrote on last edited by jhonnygolpe
          #11

          [EDIT] I've found that I missed a return; call on the receive() function... and now it's working fine...
          Really I'm not sure where it fails. And yes, the next step it's write a lot of 'DEBUG'. I've tested changing the eeprom address with the same results, so I'm assuming the fault it's in my code :worried:
          But always falls after a downAction movement...

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          • mfalkviddM Offline
            mfalkviddM Offline
            mfalkvidd
            Mod
            wrote on last edited by
            #12

            I think it hangs in this loop:

            while ( valueU == HIGH
                              && ((nowMillis - startMillis) / OPERATION_TIME) < 100
                              && (positionValue + ((nowMillis - startMillis) / OPERATION_TIME)) < 100
                              &&  (nowMillis - startMillis) < OPERATION_TIME );
            

            None of the variables in this loop will be updated while the loop is running, so it will run forever. I don't know what you wanted to do, but I don't think you wanted an infinite loop.

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            • J Offline
              J Offline
              jhonnygolpe
              wrote on last edited by
              #13

              Not really... inside the do loop, that it's repeated anytime, updates valueU and nowMillis values, so it's not an infinite loop.
              I think it was a problem with the receive function... after calling

              
                  else {
                    moveBlind(dimvalue); 
                    return;
                  }
                }
              

              the moveBlind function I missed the return;
              Now it seems to work fine.... I'm sure I'll have some more errors, but i'm satisfied by the moment.
              Thanks a lot to everybody

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              • mfalkviddM Offline
                mfalkviddM Offline
                mfalkvidd
                Mod
                wrote on last edited by mfalkvidd
                #14

                What's inside the while loop? To me it looks like nothing. There is no { after the while conditions, just a ;. The ; means that the while loop has no contents except re-evaluating the conditions.

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                • J Offline
                  J Offline
                  jhonnygolpe
                  wrote on last edited by
                  #15

                  It's a

                  do { 
                  ...t 
                  } while();
                  

                  loop. It's similar to the while, but with this one you can control that the routine inside the do{...} it's always executed at least once.

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                  • J Offline
                    J Offline
                    jhonnygolpe
                    wrote on last edited by
                    #16

                    Nevertheless I must review all my code.... It's been working for a time... But lately it freezes again

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                    • mfalkviddM Offline
                      mfalkviddM Offline
                      mfalkvidd
                      Mod
                      wrote on last edited by
                      #17

                      Oh. Sorry. I wasn't aware of the do-while construct. Thanks for teaching me.

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