How can i detect 230V (pump active)?
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Hi all,
i hope you have an idea. The situation: I have a water-bearing fireplace which is integrated into the heating system of my house. There is a temperature-sensor, which switches at 70°C so that the heatingpump gets 230V and starts
My challenge is now, to detect when the sensor closes and opens (pump on / off) without cutting the direct connection (the direct wire) between 230V, Sensor and Pump (legal requirement).
My first thought was to install a relay in parallel to the pump. But this draws 1W - a bit too much for me.
My question is now: How can i easily detect, when the pump is on and off? Any Ideas?
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A non-invasive current sensor?
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@ahhk you can use something like "Electric Field Detector", example: http://forum.arduino.cc/index.php?topic=85752.0
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Hi,
sry guys, i withdraw my question. I just found a simple and unbelievable easy solution: 230v small signal lamp + LDR.
It could not be cheaper and easier.....LOL
Thx for your proposals!
GreetingsAndreas
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What's a 'small signal lamp', and how much power does it draw?
I'm looking for a similar solution - I want to monitor my central heating and hot water system. I've got a UK 'Y-plan' system, with a mid-position valve. One wire to the valve is energised (i.e., 230V) when heating is on, while another is energised when hot water is off.
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Hi,
something like this: http://www.ebay.com/itm/Signalleuchten-mit-Lampe-Max-230-V-Rot-transparent-RAFI-Inhalt-1-St-/400562275133?hash=item5d435f433d
On the arduino-side, just use an LDR (http://www.ebay.com/itm/20PCS-Photoresistor-LDR-CDS-5mm-Light-Dependent-Resistor-Sensor-GL5516-Arduino-/311050784623?hash=item486c124f6f)
The LDR triggers an interrupt and the arduino wakes up to send "on" or "off" signal
Greetings
Andreas
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I'm trying to detect mains voltage as suggested above, using a miniature mains neon indicator and photodiode sensor module (digital output):
(http://www.ebay.co.uk/itm/301337737695?_trksid=p2060353.m2749.l2649&ssPageName=STRK%3AMEBIDX%3AIT)
(http://www.ebay.co.uk/itm/161785822980?_trksid=p2060353.m2749.l2649&ssPageName=STRK%3AMEBIDX%3AIT)I'm using the MySensors Door / Windows / Button example sketch, however in serial monitor I'm getting rapidly alternating fail messages:
send: 1-1-0-0 s=3,c=1,t=16,pt=2,l=2,st=fail:0 send: 1-1-0-0 s=3,c=1,t=16,pt=2,l=2,st=fail:1 send: 1-1-0-0 s=3,c=1,t=16,pt=2,l=2,st=fail:0 send: 1-1-0-0 s=3,c=1,t=16,pt=2,l=2,st=fail:1 send: 1-1-0-0 s=3,c=1,t=16,pt=2,l=2,st=fail:0 send: 1-1-0-0 s=3,c=1,t=16,pt=2,l=2,st=fail:1
Is this because the input is changing at 50Hz? (it works OK on a battery-powered torch).
Is there anything I can do to overcome this?
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@MikeF Just a guess.. I think a Neon - Photodiode combination is to fast. A LDR is a rather slow analog device which can be damped with a capacitor in parallel. You could try it with the photo diode and a 0.1 - 1.0 uF value. The fails are probably because the radio cannot keep up with the speed (50 Hz => one message each 10ms )
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Success! with 1.0uF across photodiode, although pot adjustment setting is quite sensitive. May try replacing photodiode with LDR.
Thanks!
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Hi,
or use a small bulb instead neon...should also work. But a cap in parallel is always a good idea for this.